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Hi there.
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So for this problem, the information that we are given is that the height of this cylinder is a that we're going to call age is given and that is 26 centimeters.
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And it has a diameter.
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So with that diameter, we know that that is eight centimeters.
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So we know that the radius is half of the diameter.
00:27
So that will be four centimeters.
00:29
We are told that but the metal in the top and the bottom is 0 .3 centimeters thick, and the metal in the sides is 0 .05 thick.
00:41
So what we need to find in this case is to estimate the amount in a closed cylindrical can.
00:48
Now, what we need to determine is that differential in the volume.
00:53
Now, the differential in the radius is given, and that is just simply 0 .05 centimeters.
01:05
And the differential in the height is also given.
01:11
But remember that we need to take into account because we have a top and bottom, so that will be two times the value that we are given, so that will give us 2 times 0 .3 centimeters.
01:23
So that will give us a differential in the height of 0 .6 centimeters...