Question

1. Use either the Direct Comparison Test (DCT) or the Limit Comparison Test (LCT) to determine whether the series sum_{n=1}^{infty} frac{n^2 + 2n}{sqrt{n^6 + n - 1}} converges or diverges

Name: 1. Use either the Direct Comparison Test (DCT) or the Limit Comparison Test (LCT) to determine whether the series sumn=1^infty fracn^2 + 2nsqrtn^6 + n - 1 converges or diverges
Uploaded: 2023-03-31T09:37:28-08:00
Duration: 2 min 16 s
Channel: Sri K
Description: 1. Use either the Direct Comparison Test (DCT) or the Limit Comparison Test (LCT) to determine whether the series sumn=1^infty fracn^2 + 2nsqrtn^6 + n - 1 converges or diverges

          1. Use either the Direct Comparison Test (DCT) or the Limit Comparison Test (LCT) to determine whether the series sum_{n=1}^{infty} frac{n^2 + 2n}{sqrt{n^6 + n - 1}} converges or diverges

$1. Use either the Direct Comparison Test (DCT) or the Limit Comparison Test (LCT) to determine whether the series sumn=1^infty fracn^2 + 2nsqrtn^6 + n - 1 converges or diverges$

Added by Kevin W.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Sri K

03/31/2023

Step 1

We can use the Limit Comparison Test (LCT) to compare our given series with the harmonic series. To apply the LCT, we need to find the limit of the ratio of the terms of the two series as $n$ goes to infinity: $$\lim_{n \to \infty} \frac{\frac{n^2 + 3n + 2}{n^3 Show more…

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