00:01
Given that plane is given by x minus y plus z, it is equal to 7.
00:08
So, the normal vector to the plane will be the coefficients of x, y and z that is 1, minus 1 and 1.
00:17
So, it is 1, minus 1 and 1.
00:21
So, the point you check would have to be some multiple of this vector added to point is given as 382.
00:29
So, our point, required point will be 382 plus some constant multiplied by this normal vector that is 1, minus 1, 1.
00:43
This is equal to 3 plus c, 8 minus c and it is 2 plus c.
00:52
So, this is the point p which we have to find.
00:55
If we find here c, then this putting this value here of c, we get the required point p.
01:03
Put this value, point has satisfy the plane equation.
01:07
This point has satisfying the plane equation.
01:10
So, we can write here, this is suppose x coordinate, this is y and this is z coordinate.
01:16
So, this must satisfy the equation of a plane.
01:19
That is it must satisfy x minus y plus z, it is equal to 7.
01:27
This equation must be satisfied...