00:01
In this problem, we want to prove by induction that the sum from k equals 1 to n of 2k minus 1 is equal to n squared.
00:12
So as the problem requests, in order to prove this by induction, we're first going to need to show the base case is true for p of 1.
00:21
And then we're going to have to show the inductive hypothesis for any p for p of k for any k.
00:30
And then we're going to have to show that the inductive hypothesis is true and that for any k greater than or equal to one, if p of k is true, then that also means p of k plus one is true.
00:47
So for the base case, p of one just shows us that if we plug the value of one into n for this equation, well, what would we get? we get the sum from 1 to 1 of 2 times k really is equal to 1 squared.
01:08
Right? so this does just the sum from 1 to 1 of 2k minus 1 is really just equal to 2 times 1.
01:20
And so 2 times 1 minus 1 is equal to 1 squared.
01:25
That's pretty straightforward for the base case.
01:28
Now, the inductive hypothesis is the statement that for all k greater than equal to 1, because 1 is the base case, if p of k is true, then p of k plus 1, it must also be true.
01:44
So in our case, that means that this will follow.
01:50
So for our case, the inductive hypothesis is that for all k is greater than equal to 1...