00:01
Hi, so here in this question we have to find out the voltage across the load resistor using norton's theorem.
00:09
So first step, we will short the circuit or remove the load resistance rel.
00:25
So if we short the circuit, the total resistance rt will be equal to 5 oom plus 10 oom parallel to 10 oom, that is this 3 .3.
00:41
Resistors are connected in parallel so 10 into 10 divided by 10 plus 10.
00:47
On solving we will get this as 10 omens.
00:52
Now from this we will get the current i will be equal to voltage divided by total resistance that will be equal to total current.
01:01
So this will be 100 divided by 10 that is again 10 ampere.
01:07
Now from that we have short the circuits so the short circuit.
01:12
Current or i norton current will be equal to tain that is i t into ten divided by ten plus ten that is ten that is i t into this will be the resistor register t divided by ten plus ten on solving we will get again this value as five ampere now next step is short the voltage and open r .n.
01:48
So from that we will get norton resistor.
01:52
R .n...