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Use Separation of Variables to find the general solution. $y' - \frac{24x^2}{y^3} = 0$ 

          Use Separation of Variables to find the general solution.
$y' - \frac{24x^2}{y^3} = 0$
Use Separation of Variables to find the general solution. y' - (24x^2)/(y^3) = 0

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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Use Separation of Variables to find the general solution. y^(')-(24x^(2))/(y^(3))=0 Use Separation of Variables to find the general solution 24x2 = 0 v3
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Transcript

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00:01 Hi, in this question given that x square y y dash equals e power y.
00:08 We need to find the general solution by using the separation of variables.
00:13 On separating then we get x square y here y dash can be written as dy by dx equals e power y.
00:21 So, on separating y in left side and x's right side then we get y by e power y into dy equals dx divided by x square which implies y into e power minus y dy equals here x power minus 2 into dx.
00:52 On integrating both sides then we get here y minus e power minus y minus here e power minus y into 1 equals here we get x power minus 2 plus 1 divided by minus 2 plus 1 plus c...
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