00:01
Hello students, we know that double integration on the region s, carl f dot ds is equal to closed integration on c, f dot dr.
00:15
So, given that f of x comma y comma z is equal to minus 5 yz i plus 5 xz j plus 17 into x square plus y square k and the surface s which is the part of the parabola z equal to x square plus y square that lies inside the cylinder x square plus y square equal to 1 and is oriented upward.
00:49
So, the carl f is equal to del del x comma del del y comma del del z cross minus 5 yz comma 5 xz comma 17 into x square plus y square.
01:12
So, this is equal to 17 minus 5 z, this is equal to 17 minus 5 z comma minus 17 z comma 5 x minus 5 y.
01:27
Now we need to parametrize the surfaces since s is the part of the paraboloid we use the cylindrical coordinates x equal to r cos theta, y equal to r sin theta and z equal to r square where r ranges from 0 to 1 and theta ranges from 0 to 2 pi.
01:53
So, now we can compute ds which is the differential area element on the surface s, the differential area element ds is equal to absolute value of delta of x comma y by del r theta into da...