We need to find the third derivative, \(f'''(x)\).
First, let's find the first derivative, \(f'(x)\), using the power rule: \[\frac{d}{dx}(ax^n) = n(ax^{n-1})\]
So, \(f'(x) = 9(8x^{9-1}) = 72x^8\).
Now, let's find the second derivative, \(f''(x)\), using the
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