Use the Direct Comparison Test to determine whether the following series converges or diverges. ?_{n=1}^{?} frac{1}{4n^2 + 1} Choose the correct choice below. A. The series is convergent because 0 ? ?_{n=1}^{?} frac{1}{4n^2 + 1} < ?_{n=1}^{?} frac{1}{n^3} for all n and ?_{n=1}^{?} frac{1}{n^3} is convergent. B. The series is divergent because 0 ? ?_{n=1}^{?} frac{1}{n} < ?_{n=1}^{?} frac{1}{4n^2 + 1} for all n and the harmonic series is divergent. C. The series is convergent because 0 ? ?_{n=1}^{?} frac{1}{4n^2 + 1} < ?_{n=1}^{?} frac{1}{n^2} for all n and ?_{n=1}^{?} frac{1}{n^2} is convergent. D. The series is divergent because 0 ? ?_{n=1}^{?} frac{1}{n^2} < ?_{n=1}^{?} frac{1}{4n^2 + 1} for all n and ?_{n=1}^{?} frac{1}{n^2} is divergent.
Added by Joseph J.
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To do this, we need to find a series that we can compare it to. A good choice is the series: $$\sum_{n=1}^{\infty} \frac{1}{n}$$ This is the harmonic series, which is known to be divergent. Now, let's compare the terms of the two series: Show more…
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