The disk method formula is given by:
$$V = \pi \int_{a}^{b} [f(x)]^2 dx$$
In our case, $f(x) = \sqrt{x}$, $a = 0$, and $b = 8$. So, we have:
$$V = \pi \int_{0}^{8} (\sqrt{x})^2 dx$$
$$V = \pi \int_{0}^{8} x dx$$
Now, we integrate:
$$V = \pi
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