Use the following reactions to find Hrxn for this following reaction. 1/2 H2(g) + 1/2 Cl2(g) --> HCl (g) N2 (g) + 3H2 (g) --> 2 NH3 (g) H =-70.2 kJ N2 (g) + 4H2 (g) + Cl2 (g) --> 2NH4Cl (s) H = -791 kJ NH3 (g) + HCl (g) --> NH4Cl (s) H = -116 kJ

Name: use the following reactions to find hrxn for this following reaction 12 h2g 12 cl2g hcl g n2 g 3h2 g 2 nh3 g h 702 kj n2 g 4h2 g cl2 g 2nh4cl s h 791 kj nh3 g hcl g nh4cl s h 116 kj 95305
Uploaded: 2022-12-05T09:49:30-08:00
Duration: 5 min 1 s
Channel: Adi S
Description: use the following reactions to find hrxn for this following reaction 12 h2g 12 cl2g hcl g n2 g 3h2 g 2 nh3 g h 702 kj n2 g 4h2 g cl2 g 2nh4cl s h 791 kj nh3 g hcl g nh4cl s h 116 kj 95305

          Use the following reactions to find 
Hrxn for this following reaction.
1/2 H2(g) + 1/2 Cl2(g) --> HCl (g)
N2 (g) + 3H2 (g) --> 2 NH3 (g) 
H =-70.2 kJ
N2 (g) + 4H2 (g) + Cl2 (g) --> 2NH4Cl (s) 
H = -791 kJ
NH3 (g) + HCl (g) --> NH4Cl (s) 
H = -116 kJ

Added by Xavier F.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

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Solved by Expert Adi S

12/05/2022

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Use the following reactions to find Hrxn for this following reaction. 1/2 H2(g) + 1/2 Cl2(g) --> HCl (g) N2 (g) + 3H2 (g) --> 2 NH3 (g) H =-70.2 kJ N2 (g) + 4H2 (g) + Cl2 (g) --> 2NH4Cl (s) H = -791 kJ NH3 (g) + HCl (g) --> NH4Cl (s) H = -116 kJ