Use the formula $$ \int \sin^{-1}(u) du = u \sin^{-1}(u) + \sqrt{1 - u^2} + C $$ to evaluate the following integral. $$ \int x \arcsin(3x^2) dx $$
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Step 2: Identify the substitution needed. The given integral is $\int x \arcsin(3x^2) dx$. The formula involves $\sin^{-1}(u)$ (which is the same as $\arcsin(u)$). Let $u = 3x^2$. Then, we need to find $du$. $du = \frac{d}{dx}(3x^2) dx = 6x dx$. Step 3: Adjust Show more…
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