00:04
Okay, so from the graph, let's find the values of these four expressions.
00:13
First one, okay, for part a, we have f plus g of 2.
00:18
This is equivalent to f of 2 plus g of 2.
00:24
So f of 2 is 4, okay? you find the point on the quadratic curve when x is 2.
00:35
So f of 2 is 4, plus g of 2, is 1.
00:45
4 plus 1 is 5.
00:48
F minus g of negative 1, this is equivalent to f of negative 1 minus g of negative 1.
01:01
So f of negative 1 is 1.
01:04
1 minus g of negative 1.
01:06
G of negative 1 is 4...