Use the Hardy-Weinberg equations (p2 + 2pq + q2 = 1 and p + q = 1) to find the genotypes of the following hypothetical phenotypic information: a. Within a particular population, you observe that 450 individuals have freckles (dominant, F) and 550 do not have freckles (recessive, f). b. Homozygous dominant (frequency) ______(A)_________ c. Heterozygous (frequency) ______(B)_____________ d. Homozygous recessive (frequency) _______(C)____________
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Given: Frequency of dominant allele (F) = 0.45 Frequency of recessive allele (f) = 0.55 Using the Hardy-Weinberg equation: p2 + 2pq + q2 = 1 Substitute the values: (0.45)^2 + 2(0.45)(0.55) + (0.55)^2 = 1 0.2025 + 0.495 + 0.3025 = 1 0.2025 + 0.495 + 0.3025 = 1 1 Show more…
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The genotypic and allelic frequencies of a population at the Hardy-Weinberg equilibrium is described by the equation: p2 + 2pq + q2 = 1 Analyze the pairing given below. If properly paired indicate "A" but if improperly paired indicate "B" for your answer. p : frequency of recessive allele
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