00:01
Hello everyone, let's start the question.
00:03
In the first part here we need to mention the dissociation of the compounds of the acids and the equilibrium constant.
00:09
The first part of the question involves hypochlorous acid, that is h -o -cl.
00:15
If we write its dissociation, it will be written as it establishes an equilibrium releasing h plus and this o -cl negative ion.
00:26
If we write its equilibrium constant that is ka because the dissociation of acid is taking place, it will be equal to the concentration of h plus multiplied by the concentration of ocl negative divided by the concentration of h .ocl.
00:43
The value for this is equal to 3 .0 multiplied by 10 -wase to the par minus 8.
00:49
Now let's write the second part of the question in which we have to write this dissociation for propionic acid.
00:58
It is ch3, ch2, c .o .h.
01:03
It establishes an equilibrium releasing h3o positive when dissolved in water and ch3 -ch2 -c -o -negative.
01:13
The value of ka for this is given and you need to write this expression.
01:18
It will be equal to the concentration of hydronium ion multiplied by the concentration of this ion, that is ch3, ch2, coo negative, divided by the concentration of the asset...