Question

Use the Laws of logarithms to rewrite the expression \(\ln\left(\frac{x^7\sqrt{x-1}}{3x-12}\right)\) in a form with no logarithm of a product, quotient or power. After rewriting we have \(\ln\left(\frac{x^7\sqrt{x-1}}{3x-12}\right) = A\ln(x) + B\ln(x-1) + C\ln(3x-12)\) with the constant A = ___ the constant B = _ and the constant C = ___

          Use the Laws of logarithms to rewrite the expression
\(\ln\left(\frac{x^7\sqrt{x-1}}{3x-12}\right)\)
in a form with no logarithm of a product, quotient or power.
After rewriting we have
\(\ln\left(\frac{x^7\sqrt{x-1}}{3x-12}\right) = A\ln(x) + B\ln(x-1) + C\ln(3x-12)\)
with the constant A = _____
the constant B = _____
and the constant C = _____

Use the Laws of logarithms to rewrite the expression
ln((x^7√(x-1))/(3x-12))
in a form with no logarithm of a product, quotient or power.
After rewriting we have
ln((x^7√(x-1))/(3x-12)) = Aln(x) + Bln(x-1) + Cln(3x-12)
with the constant A =
the constant B =
and the constant C =

Added by Brian C.

Calculus: Early Transcendentals

James Stewart 8th Edition

Thanks for your feedback!

Use the Laws of logarithms to rewrite the expression ln((x^(7)√(x-1))/(3x-12)) in a form with no logarithm of a product, quotient, or power. After rewriting we have ln((x^(7)√(x-1))/(3x-12)) = Aln(x) + Bln(x-1) + Cln(3x-12) with the constant A =, the constant B =, and the constant C = Use the Laws of logarithms to rewrite the expression xx-1 ln 312 in a form with no logarithm of a product, quotient, or power. After rewriting we have x7√x-1 ln 312 Aln + Bln(x-1) + Cln3x=12 with the constant A, the constant B, and the constant C