Question

6. Use the method of substitution to evaluate the following indefinite integrals. (a) ? x sin(4x²) dx A. 1/2 x² cos(4x²) + C B. -1/2 x² cos(4/3 x³) C. 1/8 cos(4x²) + C D. -1/8 cos(4x²) + C (b) ? x² ?(x³ + 8) dx A. 2/9 (x³ + 8)^(3/2) + C B. 2/3 (x³ + 8)^(3/2) + C C. 1/3 x³ ?(1/4 x? + 8x) + C D. 2x?(x³ + 8) + 3x? / (2?(x³ + 8)) + C

          6. Use the method of substitution to evaluate the following indefinite integrals.
(a) ? x sin(4x²) dx
A. 1/2 x² cos(4x²) + C B. -1/2 x² cos(4/3 x³)
C. 1/8 cos(4x²) + C D. -1/8 cos(4x²) + C
(b) ? x² ?(x³ + 8) dx
A. 2/9 (x³ + 8)^(3/2) + C B. 2/3 (x³ + 8)^(3/2) + C
C. 1/3 x³ ?(1/4 x? + 8x) + C D. 2x?(x³ + 8) + 3x? / (2?(x³ + 8)) + C

6. Use the method of substitution to evaluate the following indefinite integrals.
(a) ? x sin(4x²) dx
A. 1/2 x² cos(4x²) + C B. -1/2 x² cos(4/3 x³)
C. 1/8 cos(4x²) + C D. -1/8 cos(4x²) + C
(b) ? x² ?(x³ + 8) dx
A. 2/9 (x³ + 8)^(3/2) + C B. 2/3 (x³ + 8)^(3/2) + C
C. 1/3 x³ ?(1/4 x? + 8x) + C D. 2x?(x³ + 8) + 3x? / (2?(x³ + 8)) + C

Added by -Ngeles C.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

09/03/2023

Step 1

Let's use the substitution: u = 4x Then, we have: du = 4 dx Now, we can rewrite the integral in terms of u: ∫ sin(4x) dx = ∫ (1/4) sin(u) du Show more…

Show all steps