Use the Product Rule to compute the derivative: \frac{d}{dt}((t^2+1)(t+9))\Big|_{t=-9}

Name: Use the Product Rule to compute the derivative: (d)/(dt)((t^2+1)(t+9))|t=-9
Uploaded: 2020-02-09T04:55:31-08:00
Duration: 33 s
Channel: Alex Johnson
Description: Use the Product Rule to compute the derivative: (d)/(dt)((t^2+1)(t+9))|t=-9

          Use the Product Rule to compute the derivative: \frac{d}{dt}((t^2+1)(t+9))\Big|_{t=-9}

Added by Ronald H.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Alex Johnson

02/09/2020

Step 1

The Product Rule states that if you have two functions u(t) and v(t), then the derivative of their product is given by: \[ \frac{d}{dt}(u(t)v(t)) = u'(t)v(t) + u(t)v'(t) \] In this case, let u(t) = t^2 + 1 and v(t) = t + 9. We need to find u'(t) and v'(t) Show more…

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