Use the standard reduction potentials located in the 'Tables' linked above to calculate the standard free energy change in kJ for the reaction: 3I2(s) + 2Cr(s) ? 6I-(aq) + 2Cr3+(aq) Answer: kJ K for this reaction would be than one.
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54 \text{ V} + (-0.73 \text{ V})\) \(E^\circ = 1.27 \text{ V}\) Show more…
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Use standard reduction potentials to calculate the standard free energy change in kJ for the following reaction: I2(s) + Cu(s) → 2I-(aq) + Cu2+(aq) Answer: __________ kJ
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Given the following two standard reduction potentials, $$\begin{array}{ll}\mathrm{M}^{3+}+3 \mathrm{e}^{-} \longrightarrow \mathrm{M} & 8^{\circ}=-0.10 \mathrm{V} \\ \mathrm{M}^{2+}+2 \mathrm{e}^{-} \longrightarrow \mathrm{M} & \mathscr{E}^{\circ}=-0.50 \mathrm{V} \end{array}$$ determine for the standard reduction potential of the half-reaction $$ \mathrm{M}^{3+}+\mathrm{e}^{-} \longrightarrow \mathrm{M}^{2+}$$ (Hint: You must use the extensive property $\Delta G^{\circ}$ to determine the standard reduction potential.)
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