Use the Substitution Formula, \( \int_{a}^{b} f(g(x)) \cdot g^{\prime}(x) d x=\int_{g(a)}^{g(b)} f(u) \) du where \( g(x)=u \), to evaluate the following integrals. a. \( \int_{0}^{1} t \sqrt{36+13 t} d t \) b. \( \int_{1}^{25} t \sqrt{36+13 t} d t \) a. \( \int_{0}^{1} t \sqrt{36+13 t} d t= \) b. \( \int_{1}^{25} t \sqrt{36+13 t} d t= \)
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