Use the table of values that gives values of \( f \) for selected values of \( x \). \begin{tabular}{|c|c|c|c|c|} \hline \( \boldsymbol{x} \) & -2 & -1 & 1 & 2 \\ \hline \( \boldsymbol{f}(\boldsymbol{x}) \) & -5 & 3 & 7 & 1 \\ \hline \end{tabular} Which statement is true about the roots of \( f \) ? There are no roots. There is a root between 3 and 7 . There is a root between -2 and 2 . No conclusion can be made about roots.
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The table provides the values of \( f(x) \) for \( x = -2, -1, 1, \) and \( 2 \). Show more…
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In Exercises 65–68, you may use a graphing calculator to solve the problem. Multiple Choice Let $f(x)=\left(x^{2}+1\right)(x-2)+7$ Which of the following statements is not true? $\begin{array}{l}{\text { (A) The remainder when } f(x) \text { is divided by } x^{2}+1 \text { is } 7} \\ {\text { (B) The remainder when } f(x) \text { is divided by } x-2 \text { is } 7} \\ {\text { (C) } f(2)=7} & {\text { (D) } f(0)=5} \\ {\text { (E) } f \text { does not have a real root. }}\end{array}$
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