00:01
It's a regulatory region.
00:01
The question asks you to find out, discuss, and compare the regulatory of this lac operon in the two following conditions.
00:12
Let's look at the first one.
00:14
So first of all, i put down the structure of lac gene operon on the board.
00:19
The first region is called laci.
00:21
This produces a repressor.
00:23
Then you have a cluster of lac regulatory region with a gene.
00:27
You have a cap binding site, which is in front of or upstream of the promoter region p.
00:33
The promoter region is followed by an operator region o.
00:36
It's a regulatory region.
00:38
Then you have three structure genes, z, y, and a.
00:41
Let's take a look at the first one.
00:44
The first one is the presence of high level of lactose and absence of glucose.
00:49
So in this case, let's say plus lac lactose minus glucose.
00:57
So eucalyptus prefer to use glucose as a energy source, but when the energy source glucose is not available, then it turn on this lactobacillus.
01:08
So what happened is when the repressor is expressing, it will express a repressor.
01:20
Normally without the lactose, it will actually bind to the operator region.
01:28
This will block the polymerase from moving through and produce the gene product of z, y, and a.
01:38
But with the help of lactose, which is an inducer, this inducer changed the conformation of repressor.
01:58
So you can see this is the lactose that that bind to the repressor as allos leptose.
02:05
As a result, the repressor is not able to bind to the operator region anymore.
02:11
It's open.
02:12
This is inactive or deactivated.
02:18
It can no longer bind to the operator region...