Use variation of parameters to solve the given nonhomogeneous system.\ $X' = egin{pmatrix} 0 & 3 \ -1 & 4 end{pmatrix} X + egin{pmatrix} 4 \ -4 end{pmatrix} e^t$\ $X(t) = $
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The given system is X'(t) = AX(t) + F(t), where A is a matrix and F(t) is a vector. In this case, we have: A = 0 F(t) = \begin{bmatrix} x(t) \\ (-4)e^t - 1 \end{bmatrix} Show more…
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