Question

Using a sample of size n = 501, Y is regressed against X. The fraction of the variation in Y explained by the linear relationship between X and Y is 0.5. The sum of the squares of the deviations of the actual Y-values from their mean is 900,000. What is the standard deviation of the predicted Y-values?

Name: using a sample of size n 501 y is regressed against x the fraction of the variation in y explained by the linear relationship between x and y is 05 the sum of the squares of the deviations o 64159
Uploaded: 2023-08-04T12:31:42-08:00
Duration: 3 min 15 s
Channel: Madhur L
Description: using a sample of size n 501 y is regressed against x the fraction of the variation in y explained by the linear relationship between x and y is 05 the sum of the squares of the deviations o 64159

          Using a sample of size n = 501, Y is regressed against X. The fraction of the variation in Y
explained by the linear relationship between X and Y is 0.5. The sum of the squares of the
deviations of the actual Y-values from their mean is 900,000. What is the standard deviation of
the predicted Y-values?

Added by Dylan M.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Madhur L

08/04/2023

Step 1

- Sample size, \( n = 501 \) - Coefficient of determination, \( R^2 = 0.5 \) - Total sum of squares (SST), \( \sum (Y_i - \bar{Y})^2 = 900,000 \) Show more…

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Using a sample of size n = 501, Y is regressed against X. The fraction of the variation in Y explained by the linear relationship between X and Y is 0.5. The sum of the squares of the deviations of the actual Y-values from their mean is 900,000. What is the standard deviation of the predicted Y-values?