14. Using Boolean algebra, simplify the following expressions: a. (A + \overline{B}) (A + C) b. \overline{A}B + \overline{A}B\overline{C} + \overline{A}BCD + AB\overline{C}\overline{D}E c. AB + \overline{A}BC + A d. (A + \overline{A}) (AB + AB\overline{C}) e. AB + (\overline{A} + \overline{B})C + AB
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A+BA+C A+BA+C = A(1+B)+C (distributive property) = A+C (A(1) = A) Therefore, the simplified expression is A+C. Show more…
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