Question

Using Laplace transform, find the solution of the initial value problem. 1. $2y' + y = 0$, $y(0) = -3$ 2. $y'' - 4y' = 6e^{3t} - 3e^{-t}$, $y(0) = 1$, $y'(0) = -1$

          Using Laplace transform, find the solution of the initial value problem.
1. $2y' + y = 0$, $y(0) = -3$
2. $y'' - 4y' = 6e^{3t} - 3e^{-t}$, $y(0) = 1$, $y'(0) = -1$

Added by Dana G.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

08/17/2023

Step 1

For the first equation, we can write the Laplace transform of both sides as: L{2y + y} = L{0} 2L{y} + L{y} = 0 (2 + 1)L{y} = 0 L{y} = 0 So the Laplace transform of y is zero. Show more…

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