00:01
In this question we need to draw a punit square and here we have been given that john has blood group a and he has the heterozygous condition.
00:14
So, the allele for blood group is ii and if it is heterozygous condition that means one allele here has a present and one has only the recessive allele and linda here has the blood type b and she also has the heterozygous condition that means this is the condition.
00:36
Now we need to draw the punit square.
00:39
So here we will draw the box like this and then here we will write the alleles which are ia, i, i, b, i.
00:52
So this here is for john and this here is for linda.
00:57
So now the offsprings produced will have ia, i, b and here it will be ib, i and here it will be ia, i and here it will be ii.
01:12
So we can here see that this ia, ib will produce the blood group that will be ab.
01:20
This ib and i will produce the blood group that will be b here...