00:01
Hi everyone, so in the question we have to given the following data, okay? so in this data, what is this? that we denote the height at different trials, okay? this is at time trial number one, two, three, four, five and these are the timing of the trials and h1 is the height of the first high data, okay, 0 .25 as to second.
00:30
Height data 0 .37 h3 second third height data that is 0 .5 2 okay and these you heights heights are in meter here okay so first of all what we have to find out we have to find out the average time for trial number 1 okay so to find out the average time for trial number 1 we denote here we denote it by t so t average okay so this we be equal to so this will be equal to t average is always equal to 0 .2193 okay we add to all the equations that is in trial number one okay so 0 .2345 plus 0 .2437 okay plus 0 .2 .237 okay plus 0 .0 .2139 plus 0 .2 to double 8.
01:35
Okay and dividing these terms by 5.
01:40
Okay, so where is this term here? so dividing to all of these terms divided by 5 here.
01:48
Okay, so we go this is equal to 0 .22784 second.
01:55
Okay, so this is the required time average.
01:57
Okay, so this is the required time average.
02:00
Okay, so, i have not tried the value of h4 and h5 here in the question given.
02:07
So you can read it from the question and the second part what is second part is saying that we have to find out the average for second okay similarly we add all the values of second and then we go this is equal to 0 .27618 second okay, and similarly we go the value of the average third.
02:37
This will be equal to 0 .326 or 5 seconds.
02:46
Okay, so these are the values obtained from here.
02:50
Okay, then we have to find out what is step number second is saying here that we have to find the value of g in h case.
03:00
Okay to find g in each case okay so to find out the value of g here what we do we first of all we find the value of g1 here so what is g1 here so g1 is equal to 2 h1 divided by time average of first and whole square of this term okay so this will be equal to 2 x1 by 0 .25 height of first trial, okay, and dividing this term by 0 .22784 and squaring this term...