k(x) = \frac{2x^2 - 18}{x^3 + x^2 - 12x} [1] x-intercept(s) Y-intercept [1] Hole(s) [1] Vertical Asymptote(s) [1] Horizontal Asymptote(s) [1] End Behaviours [1] Sketch the graph with the information from above. [2]
Added by James L.
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2x^2 - 18 = 0 2x^2 = 18 x^2 = 9 x = ±3 Therefore, the x-intercepts are at x = 3 and x = -3. Show more…
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