Question

3) Using the phenotypic ratio, we can determine allele frequencies in the parental generation. If the homozygous trait ($q^2$) is 0.8 then q is 0.89. P Generation: Phenotypic Ratio: 20% Carbonaria Allele Frequencies: Hardy-Weinberg Equation: if $q^2$ = 0.8, then q = 0.89 80% Typica d = 0.89

          3)
Using the phenotypic ratio, we can determine allele frequencies in the parental generation.
If the homozygous trait ($q^2$) is 0.8 then q is 0.89.
P Generation:
Phenotypic Ratio: 20% Carbonaria
Allele Frequencies:
Hardy-Weinberg Equation: if $q^2$ = 0.8, then q = 0.89
80% Typica
d = 0.89

3)
Using the phenotypic ratio, we can determine allele frequencies in the parental generation.
If the homozygous trait (q^2) is 0.8 then q is 0.89.
P Generation:
Phenotypic Ratio: 20% Carbonaria
Allele Frequencies:
Hardy-Weinberg Equation: if q^2 = 0.8, then q = 0.89
80% Typica
d = 0.89

Added by Andre R.

Biology for AP Courses

Julianne Zedalis, John Eggebrecht

Instant Answer

Solved by Expert Sri K

03/11/2023

Step 1

The phenotypic ratio is 20% Carbonaria and 80% Typica. This means that the frequency of the dominant allele (p) is 0.8 and the frequency of the recessive allele (q) is 0.2. Show more…

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Using the phenotypic ratio, we can determine allele frequencies in the parental generation. If the homozygous trait (q^2) is 0.8 then q is 0.89. 3) Using the phenotypic ratio, we can determine allele frequencies in the parental generation. If the homozygous trait (q^2) is 0.8 then q is 0.89. P Generation: Phenotypic Ratio: 20% Carbonaria 80% Typica Allele Frequencies: d=0.89 Hardy-Weinberg Equation: if q=0.8, then q=0.89