Question

Using the trigonometric substitution, the integral I = ? dx / ((x^2 - 49) ?(x^2 - 49)), is equal to the integral, in terms of ?, I = ? [ ] d?. After integration and substituting back to the variable x, the final result is I = [ ] + C.

          Using the trigonometric substitution, the integral
I = ? dx / ((x^2 - 49) ?(x^2 - 49)),
is equal to the integral, in terms of ?,
I = ? [ ] d?.
After integration and substituting back to the variable x, the final result is
I = [ ] + C.

Using the trigonometric substitution, the integral
I = ? dx / ((x^2 - 49) ?(x^2 - 49)),
is equal to the integral, in terms of ?,
I = ? [ ] d?.
After integration and substituting back to the variable x, the final result is
I = [ ] + C.

Added by Jennifer A.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Vikash Ranjan

06/02/2022

Step 1

Step 1:** Let's start with the given integral: \[ \int \frac{dx}{\sqrt{x^2 - 49}} \] ** Show more…

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Using the trigonometric substitution, the integral I = ∫ dx / ((x^2 - 49) * sqrt(x^2 - 49)) is equal to the integral, in terms of ̸, I = ∫ d̸ After integration and substituting back to the variable x, the final result is I = + C.