00:01
Alright, now in this problem using the two circuits below, calculate i1, i2, v1, v2 the power pr being dissipated or absorbed by the resistor.
00:17
Right.
00:18
So now basically the conductance pg, which is represented by pg, right? assume that is equals to 2 .7 ampires vs is equal to 1 .5 volts.
00:39
Resistence is basically the value is 270 oms and g is equal to 0 .27 seconds.
00:48
Right.
00:49
So now we will solve this problem.
00:52
Basically these are the circuit given to us.
00:55
Right? so what you could say is basically this is i1.
01:00
Okay.
01:00
So what you could say is this is that is a current source right here present.
01:07
So that means this same current will be flowing through i1.
01:12
That means you can say this implies is is equals to i1.
01:18
Why? because there is no voltage drop.
01:21
Right? so this represents 2 .7.
01:24
So basically i i 1 is 2 .7 ampers itself.
01:28
Right? so this is one we have found out.
01:35
Now, v1 would be what? v1 is the potential difference here.
01:40
So that means v1 is equal to this voltage drop will be across the resistor as well, that is 270 -oom resistor.
01:50
So that means 270 multiplied by 2 .7.
01:55
2 .7 is the current because we said is the source current will be equals to the the current flowing through the circuit...