00:01
Equation, s times the quantity, 6s minus t is equal to t squared, and we're asked to solve this 4s.
00:10
So, well, if we were to go ahead and distribute, right, the s here, what we end up with is a 6 times s squared, so a 6s squared and then minus s t, okay, well, that is equal to t squared, but then if i just subtract the t squared to the other side of the equation, we get, well, minus t squared is equal to zero.
00:40
Okay.
00:41
So we have six s squared minus s t, minus t is equal to zero.
00:49
And, well, as to solve for s.
00:53
So really, i mean, this looks like it could be almost like a quadratic equation here, right? where, and basically, where we're in standard form, we have like an as squared minus, well, minus b .s, right? or, well, so again, standard form is, right, well, a, typically we think of it as ax squared plus bx plus c, right, is equal to zero.
01:23
And if we have a quadratic in this form, we can then always solve it by using the quadratic formula.
01:28
So here, right, while our variable is now s, and yes, we actually are in this form where a, right, is equal to, well, six.
01:38
B, well, b is equal to negative t, okay, because negative s -t, well, i could rewrite this as 6s squared.
01:50
You can, i guess, we write this as 6s squared instead of minus st, i could write that as minus t, right? right.
02:00
Same thing.
02:00
Multiplication is commutative.
02:02
And then, well, a minus t squared, right, is equal to zero.
02:08
So therefore, right, b is equal to, well, negative t, right? and c is equal to, well, negative t squared because we're plus c...