00:01
Okay, so you asked quite a few questions here.
00:02
I'm going to answer a few of them.
00:04
You're supposed to separate these out, just so you know.
00:07
So number three here, the first number three you have, recently a skeleton of king richard iii was found under a parking lot in england.
00:16
Tissue samples of the skeleton contained about 93 .79 % of the carbon -14 expected in living tissue.
00:24
So, i forgot to put this down.
00:29
All right, so we have 93 .79.
00:33
So this is where we're at.
00:35
That's this one.
00:36
So we'll call that 93.
00:40
No, i'm going to call it 1 .9379.
00:46
And then our original amount was 100 % or 1.
00:50
And then we'll take that times 1 half to the h.
00:53
So we need to, we need to take the natural log of each side to get this out of the exponent.
01:08
Excuse me, not the natural log, the log.
01:10
So we're going to take log 379 h times the log of 1 half.
01:25
I'm actually going to make that 0 .5 instead of 1 half.
01:29
So i'm going to just do that on my calculator.
01:33
So log 0 .9379 divided by log 0 .5.
01:44
And that would tell us that h equals 0 .0925.
01:52
So that's the number of half -lives that we have gone through.
01:55
And then h equals the time, the full time over our half -life t 1 half.
02:03
So we know that 0 .0925 equals t over our 5730 years.
02:11
So we would multiply these two numbers to find our time.
02:15
So we will take that times 5730.
02:20
And that would tell us it was 529 .99.
02:24
So we will call that 530 years.
02:30
That's the amount of time that has passed.
02:33
Okay, so our equation for this, we need to find our equilibrium constants.
02:38
We have to go through a couple of steps.
02:40
We will, first we need to determine the reduction or our cell potential for this particular cell...