00:01
In this quotient there is one voltage vv and three capacitance that is c1, c2 and c3.
00:09
As c2 and c3 are in series as these two capacitance are in series and the equivalent of this is parallel with the c1.
00:26
So first of all we have given that that is given that vb is equals to 12 volt and the value of c1 which is equals to 2 .52 mu f microfarad and c2 is equals to 2 .8 microfarad, c3 is equals to 4 .74 microfarad.
00:59
Now first of all we have to find the equivalent capacitance value that is a as in quotient c1, c2 and c3 are in series so the equivalent that is c dash equivalent is equals to or we can say c dash in series that is c2 into c3 upon c2 plus c3.
01:31
Now substituting the value we get that is c dash is equals to 2 .8 into 4 .74 upon 2 .8 plus 4 .74.
01:45
On solving this we get the value of c dash equals to 1 .77602 microfarad.
01:53
Now c dash and the c1 are in parallel.
02:05
So the c equivalent is equals to c dash plus c1 on substituting the value we get 1 .7602 plus c1 that is 2 .52 microfarad which is equals to that is 4 .28 microfarad which is the value of c equivalent.
02:33
So equivalent capacitance is equals to that is c of equivalent is equals to 4 .28 mu f which is our required answer that is the c equivalent.
03:06
Now moving to the second part that is part b in this we have to calculate the energy stored in the capacitance that is energy stored in the capacitance which is equals to mu equals to half c equivalent v square on substituting the value we get the value of minus 4 joule.
03:53
Now moving to the third part that is in part c we have to calculate the voltage across each capacitor that is voltage across each capacitor...