Vector A has components 𝐴𝑥=1.42 and 𝐴𝑦=−16.2 . What is the magnitude 𝐴 of this vector? Determine the angle 𝜃 in degrees between the calculated vector and the +𝑥 ‑axis, measured counterclockwise from the +𝑥- axis.
Added by Ana B.
Step 1
The magnitude (or length) of a vector is given by the formula: A = sqrt(Ax^2 + Ay^2) Substituting the given values, we get: A = sqrt((1.42)^2 + (-16.2)^2) A = sqrt(2.0164 + 262.44) A = sqrt(264.4564) A = 16.26 units Show more…
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