Verify that the given point is on the curve and find the lines that are (a) tangent and (b) normal to the curve at the given point. x^2y^2 = 36, (-6,1)
Added by Jose Miguel T.
Step 1
To verify this, substitute x = -6 and y = 1 into the equation: (-6)^2 * (1)^2 = 36 36 = 36 Since the equation holds true, the point (-6,1) lies on the curve. Show more…
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