Question

[(0)/(1) Points] ◻ TANAPCALC10 6.2.056. TV Viewers: Newsmagazine Shows The number of viewers of a weekly TV newsmagazine show, introduced in the 2009 season, has been increasing at the rate of 3(4+(1)/(2)t)^(-(1)/(3)),(1<=t<=6) decimal place. $3(4+\frac{1}{2}t)^{-1/3}$ $(1 \le t \le 6)$

Name: 01 points tanapcalc10 62056 tv viewers newsmagazine shows the number of viewers of a weekly tv newsmagazine show introduced in the 2009 season has been increasing at the rate of 3412t 131t6 46625
Uploaded: 2021-07-26T02:14:59-08:00
Duration: 6 min 48 s
Channel: Willis James
Description: 01 points tanapcalc10 62056 tv viewers newsmagazine shows the number of viewers of a weekly tv newsmagazine show introduced in the 2009 season has been increasing at the rate of 3412t 131t6 46625

          [(0)/(1) Points] ◻ TANAPCALC10 6.2.056.
TV Viewers: Newsmagazine Shows The number of viewers of a weekly TV newsmagazine show, introduced in the 2009 season, has been increasing at the rate of
3(4+(1)/(2)t)^(-(1)/(3)),(1<=t<=6) decimal place.
$3(4+\frac{1}{2}t)^{-1/3}$ $(1 \le t \le 6)$

01 points tanapcalc10 62056 tv viewers newsmagazine shows the number of viewers of a weekly tv newsmagazine show introduced in the 2009 season has been increasing at the rate of 3412t 131t6 46625

Added by Troy M.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Willis James

07/26/2021

Step 1

We want to find the number of viewers in 2014. The number of years between 2009 and 2014 is $2014 - 2009 = 5$. Since $t=1$ corresponds to 2009, then $t=5+1=6$ corresponds to 2014. Show more…

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[(0)/(1) Points] ◻ TANAPCALC10 6.2.056. TV Viewers: Newsmagazine Shows The number of viewers of a weekly TV newsmagazine show, introduced in the 2009 season, has been increasing at the rate of 3(4+(1)/(2)t)^(-(1)/(3)),(1<=t<=6) decimal place. $3(4+\frac{1}{2}t)^{-1/3}$ $(1 \le t \le 6)$