[20, bonus] Find the general solution to the equation $y'' + ty' - (2t^2 + 2)y = 0$. (Note: the general solution contains an integral that cannot be evaluated explicitly in terms of elementary functions. You may leave this as an integral.)
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Step 1: First, let's rewrite the given differential equation in standard form by dividing through by t^2: y^('')+ty^(')-(2t^(-2)+2)y=0 y^('')+ty^(')-2t^(-2)y+2y=0 y^('')+ty^(')-2t^(-2)y+2y=0 Show more…
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