00:01
Hi, in the given question we have to perform a cross for hair length in guinea pig in which the parental generation contains the true breed genotypes for long hair and short hair.
00:18
The long hair is the recessive phenotype whereas the short hair is the dominant phenotype.
00:33
The gamut so formed will be capital h and small edge.
00:43
The resulting f1 generation from this cross will be the heterozygous denotype for all the offspring and therefore all the offspring will be short -haired, that is, the dominant phenotype.
01:03
Therefore, this is the answer to the first part.
01:05
Coming to the second part in which we have to self -fertilize the offspring obtained in the f -1 generation.
01:16
We can predict the f -2 generation using a punez square.
01:35
The genotypes will be homozygous dominant, heterozygous, heterozygous, heterozygous, homozygous recessive.
01:46
So three out of four will be having short hairs.
01:51
In the f2 generation whereas only one will be having long hairs...