4C3H5(NO3)3(l) → 6N2(g) + O2(g) + 12CO2(g) + 10H2O(g) What is the total moles of gas that is produced if 4 moles of reactant are used? What is the mole fraction of nitrogen gas, in the product gas mixture, to three significant figures?
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Given: - 4 moles of reactant are used - The reaction produces 6 moles of nitrogen gas, 1 mole of oxygen gas, 12 moles of CO2 gas, and 10 moles of water Total moles of gas produced = 6 moles of nitrogen + 1 mole of oxygen + 12 moles of CO2 + 10 moles of Show more…
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