00:01
In this question, we need to identify the limiting reactant when 0 .125 moles of nitrogen gas reacts with 0 .125 moles of oxygen gas.
00:14
And then also calculate the number of moles of nitrogen monoxide that will form.
00:19
Now, we've used exactly the same reaction equation in the previous question.
00:24
So i've just copied the balanced equation here.
00:31
Now, in order to identify the limiting reactant, we will compare two different situations.
00:38
In the first situation, we will calculate the number of moles of nitrogen monoxide that can form from 0 .1 to 5 mils of nitrogen gas.
00:50
And in the second situation, we will calculate the number of moles of nitrogen monoxide forming from 0 .1 to 5 moles of oxygen.
01:01
And then compare these two with each other in order to identify the limiting reactant.
01:08
Now, for this purpose, we will use the mole ratio of nitrogen monoxide to nitrogen gas.
01:18
And in order to do so, we need to work with the stoichiometric coefficients here for nitrogen monoxide.
01:28
It's two for nitrogen gas.
01:30
It is one.
01:31
So the mole ratio of nitrogen monoxide to nitrogen gas will be 2 to 1.
01:39
Therefore, the number of moles of nitrogen monoxide that can form from nitrogen gas in this case will be 2 times the number of moles of nitrogen gas, which is then 2 times 0 .1 .1 .2 .2 times 0 .1.
02:01
2 5 moles and that is equal to 0 .250 .0.
02:16
On the other hand, let's see what's going to happen if we use oxygen gas here as our starting point.
02:27
Now for us to calculate the number of moles of nitrogen monoxide that can form from starting off with 0 .125 moles of oxygen gas.
02:43
We will work with the mole ratio once again...