00:01
My goodness, there's a lot of words in this question.
00:05
In addition to that, there are diagrams.
00:09
So, let me draw the diagram here.
00:13
M1, m2, and this is, they're both l here.
00:25
Then there's another diagram, m1, m2, but this time around the center, there's an angle theta.
00:46
It's free to rotate.
00:49
Frictionless pivot.
00:51
Through the center.
01:08
Okay.
01:09
Wait a minute.
01:11
I think that this is vertical.
01:15
Yes.
01:15
It even says vertical in italics.
01:18
Okay.
01:18
So this is vertical.
01:20
Okay.
01:22
Find an expression for the total energy in the vertical position.
01:33
Okay.
01:35
Well, m1 would have to be greater than m2, otherwise nothing's going to happen.
01:46
And that is given.
01:47
So i'll write that down.
01:51
Okay.
01:52
So, um, the, the total energy is going to be m1 gh plus m2g but it's a negative l.
02:22
So that's going to give me m1 minus m2g.
02:35
All right.
02:42
B, find an total mechanical energy in the rotated position.
03:02
Well, the pivot is frictionless, so it's going to be the same.
03:15
However, let's just write another equation where we're showing velocity.
03:26
So it's going to be m1g, and then it's going to be the height is going to be l, um, sine theta, plus m2g negative l, sign theta, okay? plus i omega squared, where i is going to be m2 times the distance, which would be l squared, plus m1, l squared, which would be m1 plus m2, l squared.
04:41
And omega, well, omega is v over l, but i'm not sure we really need to put that in there.
04:57
So i think i'm not going to put that in there right now.
05:00
So e, just continuing, is going to be m1 minus m2, gl sine theta, plus m1 plus m2, l squared, omega squared.
05:28
So that's probably what the book would be asking about.
05:35
C.
05:43
So how would we determine the action? angular speed.
05:49
Well, the question is just how.
05:51
So i'm going to say it...