00:01
So in this problem, we are given the following series.
00:02
We are given the series that starts at n equals one to infinity of n to the power of 100 times 100 to the power of nth divided by n factorial.
00:12
So we're going to compute the following.
00:15
So ace of n is going to equal to n to the power of 100 times 100 to the power of n divided by n factorial.
00:21
And ace of n plus one is going to equal to n plus one to the power of 100 times 100 to the power of n plus one divided by n plus one factorial.
00:33
So by the ratio test, let capital l be equal to the limit as n approaches infinity of the absolute value of the ratio between ace of n plus one and ace of n.
00:44
That's going to equal to the limit as n approaches infinity of the absolute value of n plus one to the power of 100 times 100 to the power of n plus one divided by n plus one factorial and then times the reciprocal of ace of n, which is n factorial divided by n to the power of 100 times 100 to the power of n.
01:06
Now, there's no need for the absolute value, and we can cancel some of the things out to get the limit as n approaches infinity without the absolute value here...