A 10 kg box of candy rests on a floor with a coefficient of static friction of 0.40. What is the force needed to move the box? (g = 9.8 m/s^2) What is the mass of the rock if a force of 2.4 x 10^3 N makes it accelerate horizontally at a rate of 4.0 x 10^0 m/s^2, assuming no friction? A 20 kg rock is held up by a cable that will break if the tension in the cable exceeds 240 N. At what upward acceleration will the string break?
Added by Katie G.
Step 1
8m/s^2 = 98N). So, F_friction = 0.40 * 98N = 39.2N For the second question: The force applied to the rock is given by: Show more…
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