Question

7) A baseball player swings his 1 kg bat initially at 32 m/s in order to hit a 145 g baseball traveling towards him at -43 m/s. a) If we idealize this collision as perfectly elastic, what is the bat's final velocity? (A) 0 m/s (B) 13 m/s (C) 26 m/s (D) -26 m/s (E) -52 m/s •) What is the ball's final velocity?

          7) A baseball player swings his 1 kg bat initially at 32 m/s in order to hit a
145 g baseball traveling towards him at -43 m/s.
a) If we idealize this collision as perfectly elastic, what is the bat's final
velocity?
(A) 0 m/s
(B) 13 m/s
(C) 26 m/s
(D) -26 m/s
(E) -52 m/s
•) What is the ball's final velocity?

7) A baseball player swings his 1 kg bat initially at 32 m/s in order to hit a
145 g baseball traveling towards him at -43 m/s.
a) If we idealize this collision as perfectly elastic, what is the bat's final
velocity?
(A) 0 m/s
(B) 13 m/s
(C) 26 m/s
(D) -26 m/s
(E) -52 m/s
•) What is the ball's final velocity?

Added by Amy J.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Melissa Munoz

03/06/2024

Step 1

The total momentum before the collision can be calculated as: Total momentum before = (mass of bat * velocity of bat) + (mass of ball * velocity of ball) Total momentum before = (1kg * 32 m/s) + (0.145kg * -43 m/s) Total momentum before = 32 kg*m/s - 6.235 Show more…

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A baseball player swings his 1kg bat initially at 32(m)/(s) in order to hit a 145g baseball traveling towards him at -43(m)/(s). If we idealize this collision as perfectly elastic, what is the bat's final velocity? (A) 0(m)/(s) (B) 13(m)/(s) (C) 26(m)/(s) (D) -26(m)/(s) (E) -52(m)/(s) What is the ball's final velocity? 145 g baseball traveling towards him at -43 m/s. velocity? (A) 0 m/s (D) -26 m/s (E)-52m/s (B) 13 m/s (C) 26 m/s 3 What is the ball's final velocity?