Question

A child on a sled (m = 47.0 kg) slides down a long hill starting from a rest position at a point 10.0 m higher in elevation than his finishing point. a) What is the total mechanical energy present? b) Assuming that there's no friction and no external pushes, determine the child's speed at the bottom of the hill. c) The child's speed at the bottom of the hill is actually 5.0 m/s. Explain whether or not this defies the law of conservation of energy.

          A child on a sled (m = 47.0 kg) slides down a long hill starting from a rest position at a point 10.0 m higher in elevation than his finishing point. a) What is the total mechanical energy present? b) Assuming that there's no friction and no external pushes, determine the child's speed at the bottom of the hill. c) The child's speed at the bottom of the hill is actually 5.0 m/s. Explain whether or not this defies the law of conservation of energy.
        
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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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A child on a sled (m = 47.0 kg) slides down a long hill starting from a rest position at a point 10.0 m higher in elevation than his finishing point. a) What is the total mechanical energy present? b) Assuming that there's no friction and no external pushes, determine the child's speed at the bottom of the hill. c) The child's speed at the bottom of the hill is actually 5.0 m/s. Explain whether or not this defies the law of conservation of energy.
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Transcript

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00:03 Hi, for the part of the question, total mechanical energy is equal to kinetic energy plus potential energy that is zero plus mgh.
00:27 This on substituting zero plus 47 into 9 .8 into 10 which will yield the value of total mechanical energy as 4606 joules.
00:45 Moving to the b part, by conservation of energy, initial energy should be equal to final energy or we can write this in terms of mechanical energy which is 4606 is equal to 1 by 2 mv square which is thus equal to 4606 is equal to 1 by 2 into 47 into v square and on solving for v we will get the velocity as 40 meters per second...
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