00:01
So in this question, we say that a hollow, closed, rectangular tank is made from sheet metal of negligible thickness.
00:09
The tank has a length of 2x meters, a width of x meters, and a total external surface area of 48 square meters.
00:18
I want to express, in terms of x, the height of the tank, and the volume of the tank.
00:24
Then, given that x can vary, we're going to find the dimensions of the tank for which the volume is, is a maximum.
00:32
So what do i know about the surface area of a rectangular box? i know that it's two times the length times the width plus two times the height plus two times the width times the height.
00:51
That's my formula for the surface area of a box.
00:55
Now they said that my length this time is 2x.
01:04
My width is x.
01:07
My length is 2x again.
01:13
My height is h.
01:16
My width is x.
01:20
Now my surface area is supposed to be 48.
01:25
So i now know that 48 is equal to 4x squared plus 4xxx plus 4x plus 2xh, or equivalently, 48 is equal to 4x squared plus 6x.
01:46
Now, i want to solve for the h for the height of the tank.
01:54
So what do i know? well, i can subtract 4x squared from each side.
01:59
I can say 6xh is equal to 48 minus 4x squared.
02:08
And if i divide by 6x, my h is equal to 48 minus 4x squared being divided by 6x.
02:20
So there is my height in terms of x.
02:25
Now, i also want my volume in terms of x.
02:30
Well, what do you know about the volume of a box? volume is length times width times height.
02:41
So my length this time again is 2x.
02:48
My width is x and my height is 48 minus 4x squared being divided by 6x...