Question

a. $$ \frac{-3}{16} + \frac{7}{4} $$ b. $$ \frac{1}{6} + \frac{-5}{9} + \frac{6}{3} $$ c. $$ \frac{-7}{2^3 \cdot 3^2} - \frac{-7}{2 \cdot 3^3} $$ d. $$ 9\frac{4}{5} + 7\frac{5}{7} $$ e. $$ 5\frac{1}{6} - 3\frac{5}{8} $$ f. $$ -4\frac{1}{3} - 3\frac{5}{12} $$

Name: a frac 316 frac74 b frac16 frac 59 frac63 c frac 723 cdot 32 frac 72 cdot 33 d 9frac45 7frac57 e 5frac16 3frac58 f 4frac13 3frac512 38106
Uploaded: 2022-02-06T18:20:02-08:00
Duration: 4 min 47 s
Channel: M Hassan Anwar
Description: a frac 316 frac74 b frac16 frac 59 frac63 c frac 723 cdot 32 frac 72 cdot 33 d 9frac45 7frac57 e 5frac16 3frac58 f 4frac13 3frac512 38106

          a. $$ \frac{-3}{16} + \frac{7}{4} $$
b. $$ \frac{1}{6} + \frac{-5}{9} + \frac{6}{3} $$
c. $$ \frac{-7}{2^3 \cdot 3^2} - \frac{-7}{2 \cdot 3^3} $$
d. $$ 9\frac{4}{5} + 7\frac{5}{7} $$
e. $$ 5\frac{1}{6} - 3\frac{5}{8} $$
f. $$ -4\frac{1}{3} - 3\frac{5}{12} $$

$a frac 316 frac74 b frac16 frac 59 frac63 c frac 723 cdot 32 frac 72 cdot 33 d 9frac45 7frac57 e 5frac16 3frac58 f 4frac13 3frac512 38106$

Added by Katie R.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert M Hassan Anwar

02/06/2022

Step 1

$$ \frac{-3}{16} + \frac{7}{4} $$ To add these fractions, we need a common denominator. The least common multiple of 16 and 4 is 16. Convert $$ \frac{7}{4} $$ to an equivalent fraction with a denominator of 16: $$ \frac{7}{4} = \frac{7 \times 4}{4 \times 4} = Show more…

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Thanks for your feedback!

a. $$ \frac{-3}{16} + \frac{7}{4} $$ b. $$ \frac{1}{6} + \frac{-5}{9} + \frac{6}{3} $$ c. $$ \frac{-7}{2^3 \cdot 3^2} - \frac{-7}{2 \cdot 3^3} $$ d. $$ 9\frac{4}{5} + 7\frac{5}{7} $$ e. $$ 5\frac{1}{6} - 3\frac{5}{8} $$ f. $$ -4\frac{1}{3} - 3\frac{5}{12} $$