Question

4. A marketing department of a certain company is running an advertisement campaign for their product through a social media. They estimate that their advertisement would reach $x$ number of people measured in thousands, in $t$ weeks as in Problem (3b). In other words, $x(t) \approx \frac{7.0 - 2.0e^{-0.75t}}{2.0 + 3.0e^{-0.75t}}$

          4. A marketing department of a certain company is running an advertisement campaign for their product through a social media. They estimate that their advertisement would reach $x$ number of people measured in thousands, in $t$ weeks as in Problem (3b). In other words,

$x(t) \approx \frac{7.0 - 2.0e^{-0.75t}}{2.0 + 3.0e^{-0.75t}}$

4. A marketing department of a certain company is running an advertisement campaign for their product through a social media. They estimate that their advertisement would reach x number of people measured in thousands, in t weeks as in Problem (3b). In other words,

x(t) ≈(7.0 - 2.0e^-0.75t)/(2.0 + 3.0e^-0.75t)

Added by Ryan G.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Nick Johnson

09/18/2021

Step 1

They have an estimated function to calculate the number of people reached, measured in thousands, after t weeks. The function is: x(t) = (7.0 - 2.0e^(-0.75t)) / (2.0 + 3.0e^(-0.75t)) Show more…

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A marketing department of a certain company is running an advertisement campaign for their product through a social media. They estimate that their advertisement would reach x number of people measured in thousands, in t weeks as in Problem (3b). In other words, x(t)~~(7.0-2.0e^(-0.75t))/(2.0+3.0e^(-0.75t)). 4. A marketing department of a certain company is running an advertisement campaign for their product through a social media. They estimate that their advertisement would reach number of people measured in thousands, in t weeks as in Problem(3b). Ir other words, 7.0 - 2.0 e-0.75t 2.0 + 3.0 e-0.75t